4x^2+132x-432=0

Solution for 4x^2+132x-432=0 equation:

4x^2+132x-432=0

a = 4; b = 132; c = -432;
Δ = b2-4ac
Δ = 1322-4·4·(-432)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-156}{2*4}=\frac{-288}{8}
=-36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+156}{2*4}=\frac{24}{8}
=3
$